tag:blogger.com,1999:blog-8628325.post3518954375021483951..comments2024-03-15T05:59:53.929-07:00Comments on Ambivalent Engineer: Correcting a NewtonianAmbivalent Engineerhttp://www.blogger.com/profile/16491915174390340818noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-8628325.post-25806721193345393822008-03-20T09:31:00.000-07:002008-03-20T09:31:00.000-07:00Maybe... I'm not sure what you mean by the output ...Maybe... I'm not sure what you mean by the output stop. Do you mean the exit pupil?<BR/><BR/>I actually have a Paracorr, and I'd be happy to peer into it to figure out how far back the exit pupil is. I can guess at the diameter, but unless the exit pupil is projected out the back of the thing, I won't be able to measure it.<BR/><BR/>If you are referring to the little design I did (which is probably neither as good nor the same as the Paracorr), and you'd like me to send you the design, drop me an email, I can send the Zemax file over. Send to myfirstname@mylastname.com.Ambivalent Engineerhttps://www.blogger.com/profile/16491915174390340818noreply@blogger.comtag:blogger.com,1999:blog-8628325.post-52437517628350053132008-03-18T09:06:00.000-07:002008-03-18T09:06:00.000-07:00Hi,Are you able to say where the output stop of th...Hi,<BR/><BR/>Are you able to say where the output stop of the Paracorr may be and how large it is?<BR/><BR/>Cheers. Andrew.Anonymousnoreply@blogger.com